Question

A household uses the following electric appliances :

(i) Refrigerator of rating 400W for ten hours each day.

(ii) Two electric fans of rating 80W each for twelve hours each day.

(iii) Six electric tubes of rating 18W each for 6 hours each day.

Calculate the electricity bill of the household for the month of June if the cost

per unit of electric energy is Rs. 3.00.

Answer 1

Answer is explained below.

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Answer 2

A month has approximately 30 days

So, according to the data present in the question,

The electricity consumption of one day is:

I) refrigerator= (400×10)=4000 W

ii) 2 fans=(2×80×12)=1920 W

iii)6 tubes= (6×18×6)=648 W

Total: (4000+1920+648)=6568W=6.568 KW=6.6 units

Electricity consumption of one month:

(6.6×30)=198 units

Total cost =198×3=594 rs.