A household uses two electric fans each of rating 80 W for 8 hours a day and four electric tubes each of rating 20 W for 10 hours a day. Calculate the amount of electrical energy consumed (in joules) in the month of June.
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Answers
Answered by
9
Answer:
Energy consumed = power×time
Energy consumed by two electric fans = 2×80×8 = 1280Whr
Energy consumed by four electric tubes = 4×20×10 = 800Whr
Total energy consumed in a day = 1280+800 = 2080Whr = 20.8KWh
Energy consumed in the month of June = 30×2.08 = 62.4KWh
Answered by
2
Answer:
62.40 KWH
Explanation:
fans = 80w for 8hrs , no of fans = 2
energy consumed by fans = 1280w
electric tubes = 20w for 10hrs , no of tubes = 4
energy consumed by tubes = 800w
total energy consumed = 1280w+800w = 2080w
KWH = 2080/1000 = 2.08KWH
2.08 per day so in the month of june = 2.08 x 30
therefore the answer is 62.40 KWH
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