Question

A housewife, with a given amount, can buy either
10 apples or 15 oranges or 2 watermelons. Find the
maximum number of oranges which she can buy
with six times the initial amount such that she gets
each of the three varieties of fruits.
(A) 75 (B) 81 (C) 60 (D) 72​

Answer 1

Answer:

B ) 81 is the correct answer

Step-by-step explanation:

If the amount is now 6 times and he buys 1 apple and 1 watermelon she will be left with money to buy 81 oranges.

You can check this by putting any value in this.

Answer 2

Answer:

81

Step-by-step explanation:

Let

x=apple

y=orange

z=watermelon

Given,

10x=15y=2z

means

if the amount is 6 time

than we can purchase y=90

but we have to buy every thing

so initially

we can do this

10apple+60orange+2watermelon;

but we have to buy maximum orange

so, (10x=15y=2z) as we have given

1 watermelon =7.5 orange

and 1 apple=1.5 orange

so at the end we can do

1 apple+1 watermelon +( 60+ 7.5+9*1.5)orange

finally we got

60+ 7.5+9*1.5= 81 orange.