Question

A hovercraft takes off from a platform.
Its height (in meters), x seconds after takeoff, is modeled by
h(x)=-(x-11)(x+3) How many seconds after takeoff will the hovercraft land on the ground?

________seconds

Answer 1

$\bf\large\underline\pink{Answer:-}$

Step-by-step explanation:

Given A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by: h(x) = -2x^2+20x+48. How many seconds after takeoff will the hovercraft reach its maximum height.

We have the equation - 2x^2 + 20 x + 48

Since we need to find the coordinates vertex ,

x = - b/2a

x = -(20)/2(2)

x = - 20/4

x = - 5 secs

Now the hovercraft after 5 secs of takeoff reaches the maximum height

Now substitute x = 5 in the given  equation.

So - 2(5)^2 + 20(5) + 48

148 - 50

= 98 mtrs

So maximum height will be 98 mtrs

Answer 2

$\bf\large\underline\blue{Answer:-}$

Given A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by: h(x) = -2x^2+20x+48. How many seconds after takeoff will the hovercraft reach its maximum height. Now substitute x = 5 in the given equation.