Question

(a) How many moles are present in 4 g of sodium hydroxide? (b) Calculate the number of particles in 46 g of Na atom​

Answer 1

Answer: (a) 0.1mol

(b)

12.044×10^23

Explanation:

Molarmass of NaOH =4g/40g/mol

= 0.1mol

(b) no.of mol of Na = 46/23 = 2mol

So., No.of particle = 2×6.022×10^23

=12.044×10^23