Question

(a) How many moles of dioxygen are present in 64g of dioxygen?
(Molecular mass of dioxygen is 32)
(b) Calculate the amount of carbon dioxide formed by the complete combustion of 80 g of methane
aspertheequationCH4 +2O2 →CO2 +2H2O (Atomicmasses:C=12u,H=1u,O=16u)

Answer 1

Explanation:

(a) No. of Moles = Given mass

GMM

= 64

32

= 2 mol

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(b) 16 g CH4 → 44 g CO2

80 g CH4 → ? g CO2

16×5 g CH4 → 44×5 g CO2

•°• 80 g CH4 → 220 g CO2

The amount of Carbon dioxide formed - 220 g