Question

(a) How many square tiles of side 25cm will be required to cover a floor 12m
long and 10 m wide ? Also find the cost of tiles at the rate of rupees 8 per tile.


(b) Find the least number which when divided by 12 , 15 , 20 and 54 leaves remainder 8.

(c)Yashhad to travel 758 km 510m. He covered 426 km 85m by train and 175

km 940m by bus. Find the distance (in km) left to be covered .

Please tell me answer fast. .​

Answer 1

Answer:

Did you mean: (a) How many square tiles of side 25cm will be required to cover a floor 12m long and 10 m wide ? Also find the cost of tiles at the rate of rupees 8 per tile. (b) Find the least number which when divided by 12 , 15 , 20 and 54 leaves remainder 8. (c)Yashad to travel 758 kb 510m. He covered 426 km 85m by train and 175 km 940m by bus. Find the distance (in km) left to be covered . Please tell me answer fast. .

Answer 2

$\bf\red{1.~QuestioN:-}$

(a) How many square tiles of side 25cm will be required to cover a floor 12m

long and 10 m wide ? Also find the cost of tiles at the rate of rupees 8 per tile.

$\bf\green{\checkmark{AnsweR:-}}$

GiʋҽN:-

Each side of the square tile = 25 cm

Length of the floor = 12 m

Width of the floor = 10 m

Cost of each tile = Rs.8

To FiɳD:-

No. of tiles required to cover the floor = ??

Cost of tiles = ??

SoɭυƚioN:-

Side of each square tile = 25 cm

Length of the floor = 12 m

Width of the floor = 10 m

Here the measurements are given in different units.

So, at first we need to convert them into a single unit.

$\large{\boxed{\bf{\bigstar{1~m=100~cm}}}}}$

$\sf\red{:\implies12~m=12\times100=1,200~cm}$

$\sf\red{:\implies10~m=10\times100=1,000~cm}$

•°• Length = 1,200 cm & Breadth = 10,000 cm

So, the square tiles required = Area of the floor ÷ area of tile

➪   $\pink\bf{\dfrac{Area~of~floor}{Area~of~square~tile}}$

➪  Area of floor = Length × Breadth

➪ 1,200 × 1,000 = 12,00,000 cm²

➪ Area of square tile = Side × Side

➪ 25 × 25 = 625 cm²

➪  $\pink\bf{\dfrac{Area~of~floor}{Area~of~square~tile}}$

➪  $\pink\bf{\dfrac{12,00,000}{625}}$

➪ 1,920 tiles are required to cover the floor.

The cost of tiles = 1920 × 8 = Rs. 15,360

$\bf\red{2.~QuestioN:-}$

 

(b) Find the least number which when divided by 12 , 15 , 20 and 54 leaves remainder 8.

$\bf\green{\checkmark{AnsweR:-}}$

At first we need to see the LCM of 12, 15 , 20 and 54.

Next step is to add 8 with the solution.

$\bf:\implies{12=2\times2\times3}$

$\bf:\implies{15=3\times5}$

$\bf:\implies{20=2\times2\times5}$

$\bf:\implies{54=2\times3\times3\times3}$

LCM = 2 × 2 × 3 × 3 × 3 × 5

        = 540

So the required number which leaves remainder 8 is,

= 540 + 8

= 548

                       

$\bf\red{3.~QuestioN:-}$

(c)Yash had to travel 758 km 510m. He covered 426 km 85m by train and 175   km 940m by bus. Find the distance (in km) left to be covered .

$\bf\green{\checkmark{AnsweR:-}}$

Total distance Yash had to travel = 758 km 510m

Distance he covered by train = 426 km 85m

Distance he covered by bus =  175   km 940m

ie,

The distance he already covered ,

= 426 km 85 m + 175 km 940 m

=  ( 4,26,000 m + 85 m ) + ( 1,75,000 m + 940 m)

= 4,26,085 m + 1,75,940 m

= 6,02,025 m

So the distance left to be covered,

= 758 km 510 m - 6,02,025 m

= (7,58,000+ 510) - 6,02,025

= 7,58,510 - 6,02,025

= 1,56,485 m

On converting into km, we get,

$\bf\purple{:\implies\dfrac{1,56,485}{1000}=156.485}$

$\bf\purple{:\implies156.485~km}$

All Done!!♥