Question

A human patient suffering from a duodenal ulcer may show a hydrochloric acid concentration of 0.080 mol/L in his gastric juice. It is

possible to neutralize this acid with aluminium hydroxide, Al(OH)3 according to the chemical reaction shown below:
Al(OH)3 +HCl -> AlCl3 +
H2O
If the patient's stomach receives 3.0L of gastric juice per day, how much aluminium hydroxide must he consume per day to counteract the

acid? ​

Answer 1

Answer:

Moles of HCl present in 2 litres of gastric juice=0.075×2=0.15

Mass of HCl present in 2 litres of gastric juice=0.15×36.5=5.475 g

The balanced chemical equation is given by

Al(OH)

3

+3HCl→AlCl

3

+3H

2

O

According to the reaction, 109.5 g of HCl is neutralized by 78 g Al(OH)

3

Hence, 5.475 g HCl will be neutralized by

109.5

78

×5.475=3.9 g of Al(OH)

3