Question

A hummingbird can flutter its wings 4,800 times per minute.

What is the frequency of wing flutters per second?

flutters/second



What is the period for one wing flutter in seconds? Round your answer to two significant figures.

seconds

Answer 1

given, Frequency = 4800 hz

we know, 1 hour = 60 minute

frequency = 4800/60 = 80hz or 80 flutters per second

period = 1/frequency

= 1/80

= 0.0125 seconds

Hope it helps

Answer 2

The frequency and time period of wing flutters per second are 80 Hz and 0.0125 respectively.

Explanation:

As we know in simple pendulum, time period is given as

$T=\frac{t}{n}$

Here, n is the number of oscillations made by the pendulum in time t.

Frequency is given as

$f=\frac{1}{T}$

as bird flutter its wings 4800 times in 60 s.

So, time period is

$T=\frac{60}{4800} =0.0125s$

Therefore, frequency

$f=\frac{1}{0.0125}$

f = 80 Hz.

Thus, the frequency and time period of wing flutters per second are 80 Hz and 0.0125 s respectively.

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