Chemistry, asked by javesh95, 1 year ago

a hundred ml solution of KOH contains 10 Milli equivalent of KOH calculate its strength in normality and gram per litre

Answers

Answered by cuteboysk
9
N=Wa/Ea × 1000/volume
N= 56 /10 × 1000 / 100
N= 56 equi. per litre.....
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