Question

A hundred watt bulb emits monochromatic light of wavelength 400nm.calculate the number of photons emitted per second by the bulb.

Answer 1

Explanation:

● Explanation -

Energy of isolated photon is calculated by -

E = hc/λ

E = (6.63×10^-34 × 3×10^8) / (4×10^-7)

E = 4.97×10^-19 J

No of photons emitted per unit time is calculated by -

N = P / E

N = 100 / (4.97×10^-19 J)

N = 2×10^20 photons

Therefore, 2×10^20 photons are emitted.

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