a hunter 412.5m away from a cliff, moves a distance x towards the cliff and fires a gun. He hears the echo from the cliff after 2.2seconds. calculate the value of x. ( speed of sound in air =330ms-1).
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Answer:
Initial Position of the hunter = 412.5 m
Final Position of the hunter from the cliff = (412.5 - x ) m = Distance (d)
Time (t) = 2.2 s
= 2.2/2 s
= 1.1s
[Since the sound goes to the cliff, reflects and then comes to the hunter]
Speed of sound in air (S) = 330 m/s
Speed = Distance/Time
= 330 = (412.5 - x )/1.1
= 363 = 412.5-x
= x = 49.5 m
Value of x is 49.5 m or, 0.0495 km.
I hope this helps.
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