A hunter has a machine gun that can fire 50g bullets with a velocity of 900m/s. A 40Kg tiger springs at him with a velocity of 10m/s how many bullets must the hunter fire into the tiger in order to stop him in his track
Answers
F=n/t×mv here n is no.of bullets so we getF= n/t×0.05×900so F =45n/t it is equal to mv/t because F=ma and u=0 so we get n/t×45=40×10/t so we get approx as 9 bullets but we get in points because some bullets are fired but doesn't hit the target
Answer:
Mass of bullet, m = 50 g = 0.05 kg
Velocity of bullet, v = 900 ms⁻¹
Mass of tiger, M = 40 kg
Velocity of tiger, V = 10 ms⁻¹
Let n be number of bullets required to be pumped into the tiger to stop him in his track.
If the bullets and the tiger are supposed to constitute one isolated system, then the magnitude of the momentum of n bullets should be equal to the magnitude of momentum of the tiger.
∴ n × mv = MV (or)
∴ n = 40 × 100 / 0.05 × 900
= 8.89 ≈ 9