Question

A husband bursts two-thirds the number of balloons his wife bursts . in total they burst 10 balloons. How many linear equations can be written using the given information ? (a) 2 (b) 1 (c) 3 (d) 0​

Answer 1

Given :  In a balloon bursting competition for couples,

a husband bursts two-thirds the number of balloons his wife bursts.

in total they burst 10 balloons.

To Find :  linear equations  

Solution:

Let say wife burst  = 3B

then Husband burst  = (2/3)3B = 2B

Total Burst = 3B + 2B = 5B

Hence 5B  = 10

=>B= 2

Hence wife burst  = 3B = 3(2) = 6

Husband burst  =  2B= 2(2)  = 4

Here 2 Equation can be formed in 2 variable

Let say Husband burst = y  and wife burst = x

then  y  = (2/3)x

      x + y  = 10      

Solving these we can bet x = 6 and y = 4

Answer 2

Answer:

A grouped frequency table with class intervals of equal sizes using 250 -270 (270 not included in this interval) as one of the class intervals is constructed for the following data: 268, 220,368, 258, 242,310, 272, 342, 310, 290, 300, 320, 319,304,402,318, 406, 292, 354, 278, 210, 240, 330, 316, 406, 215, 258, 236. The frequency of the class 370-390 is: 5