Math, asked by imransulaimani, 10 months ago

A husband's age exceeds that of his wife by
6 years. 10 years ago, the ratio of their ages
was 5:4. Find the present age of the husband.​एक पति की उम्र 6 साल से उसकी पत्नी से अधिक है।10 साल पहले, उनकी आयु का अनुपात 5:4 था।पति की वर्तमान आयु का पता लगाएं​

Answers

Answered by ItSdHrUvSiNgH
5

Step-by-step explanation:

\huge\boxed{\fcolorbox{cyan}{grey}{Solution:-}} \\  \\

Here Given that=>

Husband's age is exceeds that of his wife by 6 years.

Let wife's age be x

and husband's age be x + 6

10 years ago....

wife's age => x - 10

husband's age => x + 6 -10 => x - 4

the ratio of their ages was 5:4

 \frac{x - 4}{x - 10}  =  \frac{5}{4} \\ 4x - 16 = 5x - 50  \\ x = 34

wife's age will be x = 34 years

husband's age will be x +6 = 40 years

Answered by parthnarkhede3
1

Answer:

let age of husband be x

then, According to the given condition

x-6 is the age of wife

Step-by-step explanation:

according to the given condition

x-10÷[(x-6)-10]=5/4

x-10÷x-16=5/4

cross multiple

4(x-10)=5(x-16)

4x-40=5x-80

4x-5x=-80+40

-x=-40

x=40

Similar questions