A hydrate of Na2So3 has 50% water in mass what is the n in Na2So3.nh2o
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We know that the molecular mass of Na2SO3 is = 126g.
Since, from the question we know that the water is 50 % by mass ,this implies that Na2SO3 is also 50 % by mass.
So, we can conclude that the ratios of Water and Na2SO3 is 1 : 1 .
Now, putting this ratios in the form of equation we get.
126/ 18 x = 1/1 .
So, 126 = 18 x.
Hence, x = 126 /18 = 7 .
Thus on solving we get the value of x = 7 hence the formula is Na2SO3.7H20.
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