A hydraulic jack can create a pressure of 750. kPa. If the diameter of the output
piston is 25.0 cm, how much force can the output piston exert?
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Answer:
36796.875 N
Explanation:
Force=Pressure×Area
Force = 750KPa × π(25/2cm)²
Force = 750 × 1000 Pa × 3.14 × (0.125m)²
Force = 36796.875 pa m² or N
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