Question

A hydraulic jack has a small piston of area 2000 cm2 and a vehicle is supported by a large piston
of area 9000 cm2

. If the force to the small piston is 2.6 x 103 N, find the weight of the vehicle when
both pistons are of the same height. In addition, find the force acting on the small piston when the
vehicle is lifted a height of 1.8 m.

Answer 1

Hydraulic lift works on the principle of pascal's law
P=
a
1
​

F
1
​

​
=
a
2
​

F
2
​

​

applying the given formula to the question.
0.90
1.2×10
4

​
=
0.2
F
​

F=
0.90
0.24×10
4

​
=2.67×10
3
N