A hydraulic lift has been constructed to lift vehicles of maximum 3000K weight. The area of crosssection of the piston's platform on which the vehicles are lifted is 580sq cm. Calculate the maximum pressure experienced on the small piston.
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Here A1 is the the area of cross-section of the smaller piston and A2 that of the bigger one.
When a force is applied on the piston X, a force will be experienced on the piston Y. Then according to Pascal"s law, pressure applied on the slide X will be equal to the pressure experienced on the side Y.
Since, P=AF
A1F1=A2F2
Area=580cm2=0.058m2
Force=3000×10=30000N
Pressure=0.0583000=517241.36Pa
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Answered by
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Answer:
pressure = 3000/0.058 = 517241.36 Pa
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