A hydraulic lift has pistion with diameter 8cm and 36cm respectively . if a force of 825N is exerted at the smaller what maximum mass can be lifted by the larger pistion
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Explanation:
Given Data:
Diameter of the small piston is
d
1
=
8.15
cm
Diameter of the large piston is
d
2
=
35.9
cm
Force applied on smaller piston is
F
1
=
825
N
Applying Pascal law to calculate the force output by the larger piston
P
1
=
P
2
[
Pressure
=
Force
Area
]
F
1
A
1
=
F
2
A
2
[
π
4
d
2
]
4
F
1
π
d
2
1
=
4
F
2
π
d
2
2
F
2
=
F
1
d
2
2
d
2
1
F
2
=
825
×
35.9
2
8.15
2
F
2
=
16007.65
N
[
F=mg,m is the mass and g is the gravitational acceleration
]
m
2
=
16007.65
9.8
m
2
=
1633.43
kg
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