Question

A hydraulic lift has piston areas of 0.4m2 and 0.1m2. If the force applied to the small piston is 100N, find the pressure and the force on the larger piston.

Answer 1

400N

According to pascal's law, force applied on any point in an enclosed liquid is transmitted to other parts of liquid equally.

Let the force applied on 0.1m^2 area be F1, force applied on 0.4m^2 area be F2.

Let the force applied on 0.1m^2 area be F1, force applied on 0.4m^2 area be F2.According to the law, pressure at the 1st point= pressure at 2nd point

P1 = P2

P1 = P2F1/0.1m^2 = F2/0.4m^2

P1 = P2F1/0.1m^2 = F2/0.4m^2100N/0.1m^2 = F2/0.4m^2

P1 = P2F1/0.1m^2 = F2/0.4m^2100N/0.1m^2 = F2/0.4m^2Therefore, F2 = 400N

This process is mostly used at garages to lift cars