Question

A hydraulic lift is designed to lift cars with maximum mass of 300 kg. The cross sectional area of the piston carrying the load is 425 cm2. What maximum pressure would the smaller piston has to bear?

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Answer 1

Answer:

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Answer 2

Answer:

Given that

Maximum mass of a car that can be lifted, m = 3000 kg

Area of cross section of piston carrying the load , A= 452 cm²

= 0.0452 m²

Maximum force exerted by the car due to its weight (F) = mg

= 3000kg × 9.8m/s²

= 29400 kgm/s²

now maximum pressure = maximum force/area

= 29400/0.0452

= 6.504 × 10^5 N/m²

Therefore the maximum pressure on the smaller piston is 6.504 × 105Pa.

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