A hydraulic lift is designed to lift heavy
objects of maximum mass 2000 kg. The
area of cross section of piston carrying
the load is 2.25 x 10-2 m2. What is the
maximum pressure the smaller piston
would have to bear?
(A) 0.8711 x 106 N/m2
(B) 0.5862 x 107 N/m²
(C) 0.4869 x 105 N/m2
(D) 0.3271 x 104 N/m²
Answers
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Answer:
Pressure =Force /Area
=2000×10/2.25 ×10^-2 [F=Mass ×Acceleration )
=200000000/225=888888.8 Pascal
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