A hydraulic lift is used to lift a car. The small piston has a radius of 5 cm and the large piston has a radius of 50 cm. If a driver applies a force of 88 N to the small piston, what is the weight of the car the large piston can support?
8.8 N
8800 N
88000 N
880 N
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Answer:
hyy...
Pressure is the amount of force acting per unit area. That is, P=F/A.
where:
p is the pressure,
F is the normal force,
A is the area of the surface on contact. Let us consider A = πr2.
Therefore, πr12F1=πr22F2.
In this case, 2021500=12W,W=3.75kg.
Hence, weight to be placed on the small piston sufficient to lift a car of mass 1500 kg is 3.75 kg.
Explanation:
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