Question

a hydraulic machine has two Pistons A and B .a force of 50 newton is exerted on piston A which has an area of cross section of 10m2 if the area of cross section of piston b is 100m2 then calculate 1. pressure on Piston b 2.force developed in Piston b 3. does this hydraulic machine acts as a force multiplier​

Answer 1

Answer:

1 ) 0.5 pa

pressure = force / area = 50 /100 = 0.5 pa

3 ) yes the are force multipiler

2 ) as multipiler

they have to exert same pressure

$\frac{f1}{a1} = \frac{f2}{a2}$

F2 = 5 N