Question

A hydraulic press contains 0.25 m^(3)(250L) of oil. Find the decrease in volume of the oil wen it is subjected to a pressure increase /_\p=1.6xx10^(7)Pa. The bulk modulus of the oil is B=5.0xx10^(9)Pa.

Answer 1

Bulk modulus of oil (B) = - [(Δp) ÷ (Δ$V/V_{0}$)]

⇒ B = $- \frac{(0.25m^{3}) (1.6 * 10^{7} Pa)}{5.0 * 10^{9}Pa}$ = ( $- 8.0$ × $10^{-4}$) $m^{3}$ = ($-0.80 L$)

Through the increase in pressure is significantly large, the fractional change in its volume is very little.

∴ Δ$V/V_{0}$  = ( $\frac{-8.0 * 10^{-4}m^{3}}{0.25m^{3}}$) = $- 0.0032$ = $- 0.32$%

Ans) When subjected to the given pressure increase, the volume of oil decreases by (-0.32%)