Question

A hydraulic press is used to lift a load of 900kgf. When the ratio of the
diameter of pump plunger and press plunger is 1 : 3. Calculate the effort
applied on the piston of pump plunger.​

Answer 1

Answer:

Answer

Load=900kgf,Effort(E)=?

Area of cross section of the press plunger =a

1

=9m

2

Area of cross - section of the pump plunger =a

2

=0.03m

2

By Pascal's law,

Pressure exerted by pump plunger = pressure exerted on press plunger.

i.e.,

E

L

=

a

2

a

1

⇒

E

900kgf

=

0.03m

2

9m

2

⇒E=

9m

2

900kgf×0.03m

2

=3kgf.

Explanation:

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