Question

A hydrocarbon 'A' (C3H8) on treatment with chlorine in presence of sunlight yielded compound 'B' as major product. Reaction of 'B' with aqueous KOH gave 'C' which on treatment with concentrated H2SO4 yielded D. Hydrogenation of D gave back 'A'. The sequence of reactions involved in above conversion is

a) Substitution, Substitution, Addition

b) Substitution, Substitution, Dehydration, Addition

c) Substitution, Dehydration, Addition, Addition

d) Addition, Substitution, Dehydration, Substitution
​

Answer 1

Answer:

(i) C

3

H

8

+Cl

2

hv

C

3

H

7

Cl+HCl[Substitution]

(ii) C

3

H

7

Cl+Aq KOH

hv

C

3

H

7

OH+KCl[Substitution]

(iii) C

3

H

7

OH

dil H

2

SO

4

C

3

H

6

+H

2

O[Dehydration]

(iv) C

3

H

6

+H

2

→C 3 H 8

[Addition

Answer 2

Answer:

answer is in the attachment given below

Hope u get it mate.....