A hydrocarbon contains 10.5 gr of carbon per gr of H. One liter vapors of hydrocarbon at 127°C and 1 atm pressure weighs 2.8 gr. The molecular formula of hydrocarbon is
(A) C6H8
(B) C7H8
(C) C5H12
(D) C8H4
Answers
Given :-
Volume, V = 1L
Temperature, T = 127°C = 400K
Pressure, P = 1 atm
Weight, W = 2.8g
To Find :-
Molecular formula of hydrocarbon.
Solution :-
We know :-
Here ,
Substitute the values :-
Molecular mass of hydrocarbon :- 92g
Let the molecular formula of hydrocarbon be .
So,
Given that, hydrocarbon contains 10.5 gram of carbon per gram of hydrogen.
So,
Substitute the values :-
Molecular formula of hydrocarbon :-
Correct option :- B
Given :-
A hydrocarbon contains 10.5 gr of carbon per gr of H. One liter vapors of hydrocarbon at 127°C and 1 atm pressure weighs 2.8 gr.
To Find :-
Molecular formula of hydrocarbon is
Solution :-
PV = nRT
P = Pressure
V = Volume
n = No. of moles
R = Universal gas constant
T = Temperature
No. of moles = Given Mass/Molar Mass
So,
PV = G/M × RT
1 × 1 = 2.8/M × 0.0821 × 400
1 = 2.8/M × 32.84
M = 2.8 × 32.84
M = 91.952 = 92 g
Now
Let us assume the formula is
Now
12p + q = 92 (1)
12p/q = 10.5 (according to the statement)
12p = q × 10.5
12p = 10.5q
10.5q + q = 92
11.5q = 92
q = 92/11.5
q = 8
Using 1
12p + 8 = 92
12p = 92 - 8
12p = 84
p = 84/12
p = 7
Hence
Molecular formula = C₇H₈
If we said to find molar mass
Molar mass = C × 7 + H × 8
Molar mass = 12 × 7 + 1 × 8
Molar mass = 84 + 8
Molar mass = 92 g/mol
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