Question

A hydrocarbon contains 82.8% carbon and has a relative molecular mass of 58. Write (i) Empirical formula, (ii) its molecular formula.

Answer 1

C = 82.8 ÷ 12 = 6.9
H = 17.2 ÷ 1 = 17.2


C = 6.9 ÷ 6.9 = 1
H = 17.2 ÷ 6.9 = 2.5
1 : 2.5
2 : 5
Empirical farmula Is c2h5
Molecular farmula Is

N= m.f mass ÷ e.f mass
N = 58÷ 29 = 2

Molecular farmula = empirical farmula × N
= (c2h5 )2
= c4 h10

Answer 2

Answer:

c4 h10

Explanation:

C = 82.8 ÷ 12 = 6.9

H = 17.2 ÷ 1 = 17.2

C = 6.9 ÷ 6.9 = 1

H = 17.2 ÷ 6.9 = 2.5

1 : 2.5

2 : 5

Empirical farmula Is c2h5

Molecular farmula Is

N= m.f mass ÷ e.f mass

N = 58÷ 29 = 2

Molecular farmula = empirical farmula × N

= (c2h5 )2

= c4 h10

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