a hydrocarbon contains 86 % carbon 448 �� of the hydrocarbon weighs1.68 � of stp. then the hydrocarbon is
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Hydro carbon 86% C and 14% H
mole ratio 86/12: 14 = 7:14 = 1:2
Empirical formula = CH2 = 14 g
Gn 448 ml at stp weighs 1.68g
22400 ml at stp weighs 22400 x 1.68/448 = 84 g
Moleculat weight of the hydrocarbon is 84
n = 84/14 = 6
Therefore the compound is C6H12.
It can be a cyclo hexane or a hexene.
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n=84/14=6
therefore,the compound is C6H12
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