a hydrocarbon contains 86% carbon. 488 ml of hydrocarbon weighs 1.68 gm at STP. Then hydrocarbon is- (a) alkane (b) alkene (c) alkyne (d) arene. choose correct option
Answers
Answered by
38
Hey Dear,
◆ Answer -
(b) Alkene
● Explaination -
Given that hydrocarbon has 86% C content.
In 100 gm hydrocarbon, mass of carbon will be 100×86% = 86 gm.
Moles of C are calculated by -
nC = 86 / 12
nC = 7.166 mol
In 100 gm hydrocarbon, mass of hydrogen will be 100-86 = 14 gm.
Moles of H are calculated as -
nH = 14 / 1
nH = 14 mol
Thus, C:H ratio will be 7.166:14 ≈ 1:2 which gives rise to empirical formula CH2.
Thus, given compound with molecular formula CnH2n must be an alkene.
Thanks dear...
Answered by
8
Answer:
Option (b) alkene
The given hydrocarbon belongs to the family of alkenes .
Explanation:
For explanation, please refer to the given attachment.
Hope it helps you.
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Attachments:
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