Chemistry, asked by rajnikantdubey3036, 10 months ago

A hydrocarbon of molecular formula C6H14 on mono chlorination gives two products. Identify the structure of hydrocarbon. ~Haloalkanes & Haloarenes

Answers

Answered by Anonymous
3

Answer:

2,3-dimethylbutane

Explanation:

Two products are provided by a hydrocarbon of molecular formula C6H14 on monochlorination. The hydrocarbon IUPAC name is 2,3-Dimethylbutane.

2,3-dimethylbutane is an alkane butane substituted at positions 2 and 3 by a methyl group. It is an alkane and an organic compound which is unstable. 2,3-dimethylbutane has a petroleum like odour and appears as a smooth, colourless liquid.

Answered by aakankshavatsal
2

Answer:

2,3-dimethylbutane [(CH3)2CH—CH(CH3)2] is the hydrocarbon with a molecular formula C6H14 when subjected to monochlorination reaction in light and yields 2 products, i.e., 1 chloro-2, 3-dimethylbutane and 2-chloro-2, 3-dimethylbutane.

The structure of 2, 3 dimethylbutane is symmetrical, and out of 6 carbon atoms which react with chlorine, 4 are identical (i.e., the methyl groups attached to the butane chain and those attached to the 2, 3 position of the hydrocarbon chain).

Furthermore, the substitution or product formation only takes place on the tertiary hydrogen atoms. The carbon atoms on the butane backbone at the 2 and 3 position consist of 2 tertiary hydrogen atoms which can be substituted to yield the chlorination products as follows:

Explanation:

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