Question

A hydrochloric acid solution consists of 28.0% HCl by mass and has a density of 1.14g/mL. This solution reacts completely with 1.36 g Al in the reaction 2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g). Determine the molarity of the AlCl3(aq) if the solution volume is simply the 17.3 mL.

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Answer 1

6HCl+2Al>>2AlCl3 + 3 H2

so 2 moles of Al reacts with 6 moles HCl

moles Al=1.35/27 so you need 6/2 * 1.35/27 moles Hcl=5.55 grams HCl

5.55=.28*1.14*Volume

solve for volume in mL

Answer 2

6HCl+2Al>>2AlCl3 + 3 H2 so 2 moles of Al reacts with 6 moles HCl moles Al=1.35/27 so you need 6/2 * 1.35/27 moles Hcl=5.55 grams HCl

5.55=.28*1.14*Volume

solve for volume in mL