a hydroelectric power station takes its water from a lake whose water level is at height of 50 metre above the turbine . assuming an overall efficiency of 40% calculate the mass of water which must flow through the turbine each second to produce water output of 1MW . ( take g = 10 ms-² )
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Answer:
5000kg.
Explanation:
P.E=mgh
P.E=m×10×50=500×mJ
40 % of this is equal to (0.4)500×m=200×m
Power=work/time 1×10^6 =200×m/1sec
m=10 ^6 /200=5000kg
Hence there is a mass of 5000kg.
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