Question

A hydrogen atom absorbs a photon with a 632 nm wavelength. If the atom was initially at ground state (n = 1), What is the final state (energy level) of the atom?

Answer 1

Answer:

hsnnsmakakamam

j

Explanation:

nnsnksmsmskakw

Answer 2

Answer:

use Ryedberg's equation that is

$\frac{1}{lambd} = r( \frac{1}{ {n}^{2 } } + \frac{1}{ {n}^{2} } )$

Explanation:

here lambda = wave length in metre

r = reydberg constant that is 10.97 × 10^-27

first n = higher energy level that is asking in the question

2nd n = lower energy level that is given 1

hope it will help you