Question

A hydrogen atom absorbs a photon with a 632 nm wavelength. If the atom was initially at ground state (n = 1), What is the final state (energy level) of the atom?

b- Find the maximum number of electrons allowed in the energy level 3 (list all possible states (n, l, ml, ms))

Answer 1

Answer:

We are given that,

Initial state of electron = n =1

final state of electron = ny = 4.

We want to calculate the frequency of photon absorbed by the electron to make this transition. As we know that energy of photon absorbed is given by.

E = - 13.6(1/(n_{f} ^ 2) - 1/(n_{i} ^ 2)) * e * V

hf = - 13.6(1/(n_{f} ^ 2) - 1/(n_{i} ^ 2)) * e * V

f = - 13.6/h * (1/(n_{f} ^ 2) - 1/(n_{i} ^ 2)) * e * V

13.6 4.14 x 10-15 eVs eV

--3.28 x 10¹1 Hz

--3.28 x 10¹5 (- - -) Hz

=-3.28 x 10¹ Hz

= -3.28 × 10¹-15 Hz 16

+3.08 x 10¹5 Hz,