Question

A hydrogen atom,an electron and an alpha particle are projected in a region of magnetic field , in a direction perpendicular to magnetic field. If F1, F2 and F3 respectively is the force acting on them, then
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Answer 1

Answer:

alpha particle experience same force in electric field as in magnetic field

So, f

E

=f

B

qE=qVB

V=

B

E

Answer 2

Given:

A hydrogen atom,an electron and an alpha particle are projected in a region of magnetic field B , in a direction perpendicular to magnetic field.

To find:

Order of magnitude of Forces experienced by the charges.

Calculation:

For any charge q , which is travelling at velocity v at an angle of $\theta$ with the magnetic field intensity B , for ce experienced be F

$\boxed{ \rm{F = q \times \{v \times B \times \sin( \theta) \}}}$

For Hydrogen :

$\rm{F1 = q \times \{v \times B \times \sin( \theta) \}}$

$\rm{ = > F1 = 1e \times \{v \times B \times \sin( 90 \degree) \}}$

$\rm{ = > F1 = ev B }$

For Electron:

$\rm{F2 = q \times \{v \times B \times \sin( \theta) \}}$

$\rm{ = > F2= 1e \times \{v \times B \times \sin( 90 \degree) \}}$

$\rm{ = > F2 = ev B }$

For $\alpha$ particle:

$\rm{F3 = q \times \{v \times B \times \sin( \theta) \}}$

$\rm{ = > F3= 2e \times \{v \times B \times \sin( 90 \degree) \}}$

$\rm{ = > F3= 2ev B }$

Hence required order :

$\boxed{ \bold{ \large{F3 > F2 = F1}}}$