Question

A hydrogen atom in ground state absorbs 10.2 ev of energy the orbital angular momentum of the electron is increased by

Answer 1

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$<b>{Electron after absorbing 10.2 eV energy goes to its first excited state (n=2) from ground state (n = 1).                     ∴ Increase in momentum  =h2π =6.6×10−346.28=1.05×10−34J}$

Answer 2

TRICK ; Check for 'increased by' in the question

Explanation:

The orbital angular momentum of an electron is given by : n h/2π

By absorbing 10.2 ev , it gets excited to the 2nd orbit

Where the angular momentum = 2h/2π

The increase in momentum = h/2π ( ie 1h/2π is at ground and taking the difference )

The increase in momentum = 6.6 x 10⁻³⁴ / 2 x 3.14

                                              = 1.05 x10⁻³⁴

                          Hope you understand

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