A hydrogen atom in ground state absorbs 10.2eV of energy.
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Orbital angular momentum of the electron in H atom in the nth state is given by:
L = n×h/2π
for ground state n = 1
L=h/2π = 6.6×10^−34/2×3.14 = 1.05×10^−34 Js
L = n×h/2π
for ground state n = 1
L=h/2π = 6.6×10^−34/2×3.14 = 1.05×10^−34 Js
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TRICK ; It is said increased by in the question
Explanation:
The orbital angular momentum of an electron is given by : n h/2π
By absorbing 10.2 ev , it gets excited to the 2nd orbit
- Where the angular momentum = 2h/2π
- The increase in momentum = h/2π ( ie 1h/2π is at ground and taking the difference )
- The increase in momentum = 6.6 x 10⁻³⁴ / 2 x 3.14
= 1.05 x10⁻³⁴
Hope you understand
This is Habel sabu .............Isn't it the Brainliest...............
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