Question

A hydrogen atom in its ground state absorbs 10.2 ev of energy. The orbital angular momentum is increased by

Answer 1

Answer : The orbital angular momentum is $1.05\times 10^{-34}\ Js$

Explanation:

The orbital angular momentum of an electron is given by :

$L=n\dfrac{h}{2\pi}$

n is the state, here n = 1

h is Planck's constant

So, $L=1\times \dfrac{6.6\times 10^{-34}}{2\times 3.14}$

$L=1.05\times 10^{-34}\ Js$

Hence, this is the required solution.

Answer 2

TRICK ; It is said increased by in the question

Explanation:

The orbital angular momentum of an electron is given by : n h/2π

By absorbing 10.2 ev , it gets excited to the 2nd orbit

Where the angular momentum = 2h/2π

The increase in momentum = h/2π ( ie 1h/2π is at ground and taking the difference )

The increase in momentum = 6.6 x 10⁻³⁴ / 2 x 3.14

                                               = 1.05 x10⁻³⁴

                          Hope you understand

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