Question

A hydrogen atom in its ground state is irradiated
by light of wavelength 970Å. Taking hc/e = 1.237
x 10-ev m and the ground state energy of
hydrogen atom as 13.6 eV, the number number
of lines present in the emission spectrum is​

Answer 1

Explanation:

The electron in the ground state of H-atom jumps to the nth state after absorbing the radiation.

Wavelength of the radiation, λ=970A

o

=970×10

−10

m

Energy gained by the electron, E

′

=

eλ

hc

eV=

970×10

−10

1.237×10

−6

=12.75eV

Thus the energy of the n

th

state, E

n

=−13.6+12.75=−0.85eV

Using: E

n

=

n

2

−13.6

eV

∴ −0.85=

n

2

−13.6

⟹n=4

Number of (emission) spectral line, N=

2

n(n−1)

=

2

4(4−1)

=6 lines

Answer 2

Answer:

A hydrogen atom in its ground state is irradiated

A hydrogen atom in its ground state is irradiated by light of wavelength 970Å Taking hc/e=1.237×10-6eV m and the ground state energy of hydrogen atom as -13.6eV the number of lines present in the emmission spectrum is.