Question

a hydrogen atom is in ground state.Then to get six lines in emission spectrum wavelength of incident radition should be​

Answer 1

The value of wavelength is λ  = 1028 Å

Explanation:

• When an electron jumps to the ground number of spectral lines emitted.
• State of nth orbit = n ( n - 1 ) / 2
• = n ( n - 1 ) / 2
• = 4 ( 4 - 1 ) / 2 = 6
• Here the value of n = 4
• When electron jumps from n = 1 to n = 4 then wavelength

λ = R [ 1 / n1^2 - 1 / n2^2 ]

λ = 1.0967 x 10^7 [ 1 / 1 - 1/ 4^2 ]

λ =  1.0967 x 10^7 x [ 1 / 1 - 1 / 16 ]

λ =  1.0967 x 10^7 x [ 15 / 16 ]

λ =  1.0967 x 10^7 x 0.9375

λ = 1.028 x 10^7

λ = 1028 x 10^3 x 10^7

λ  = 1028 Å

Thus the value of wavelength is λ  = 1028 Å

Answer 2

Answer:

The value of wavelength is λ  = 1028 Å

Explanation:

• When an electron jumps to the ground number of spectral lines emitted.
• State of nth orbit = n ( n - 1 ) / 2
• = n ( n - 1 ) / 2
• = 4 ( 4 - 1 ) / 2 = 6
• Here the value of n = 4
• When electron jumps from n = 1 to n = 4 then wavelength

λ = R [ 1 / n1^2 - 1 / n2^2 ]

λ = 1.0967 x 10^7 [ 1 / 1 - 1/ 4^2 ]

λ =  1.0967 x 10^7 x [ 1 / 1 - 1 / 16 ]

λ =  1.0967 x 10^7 x [ 15 / 16 ]

λ =  1.0967 x 10^7 x 0.9375

λ = 1.028 x 10^7

λ = 1028 x 10^3 x 10^7

λ  = 1028 Å

Thus the value of wavelength is λ  = 1028 Å