A hydrogen gas filled balloon having a mass of 25 gram is released up in the air. as the balloon descends, the gas starts leaking from it with a uniform velocity of 12cm/s and as a result, The Balloon shrinks completely in 5s. find the average force acting on the balloon.
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Answered by
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The balloon loses 25 g or 0.025 kg gas in 5 s.
So, rate of flow of gas is, dm/dt = 0.025/5 = 0.005 kg/s
Velocity of the gas, v = 12 cm/s = 0.12 m/s
Now, rate of change of momentum is,
dP/dt = d(mv)/dt
=> F = v(dm/dt) + m(dv/dt)
=> F = v(dm/dt) + 0
=> F = 0.12(0.005) = 0.0006 N
Hope this will help you.... ✌
So, rate of flow of gas is, dm/dt = 0.025/5 = 0.005 kg/s
Velocity of the gas, v = 12 cm/s = 0.12 m/s
Now, rate of change of momentum is,
dP/dt = d(mv)/dt
=> F = v(dm/dt) + m(dv/dt)
=> F = v(dm/dt) + 0
=> F = 0.12(0.005) = 0.0006 N
Hope this will help you.... ✌
Answered by
0
Answer:
-60dyne
Explanation:
Here, m= 25g u= 12 cm/s, v= 0, t=5 s
So, F= ma = m(v-u)/t = 25(0-12)/5 =-60 dyne
Also , I want to clear that please try to avoid f= ma when the question says mass is not constant, bcuz f= ma is valid only when mass is constant but here u can use that..
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