Question

A hydrogen like atom of atomic number Z is in excited state of quantum number 3n. The maximum energy which can be emitted by atom is 404eV. If it makes the transition of quantum state n a photon energy 40.4eV is emitted. The value of n will be

1) 2
2) 3
3) 4
4) 5

Answer 1

Answer:

n = 3

Refer the image .

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