A hydrulic press contain 250 litres of oil if it is subjected to an increased pressure of 1.6 × 10^7 pa . Find the decease in volume if boil = 6× 10^ 9 Nm^-2
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◀️◀️ ANSWER ▶️▶️
using the formula
B = -DELTA P / DELTA V × V
We find the decrease in volume.
we know that 1 lit. = 10^-3 m^3
so we have to find value of Delta v
6×10^9 = -1.6×10^7 /Delta v × 250 × 10^-3
Delta v = 1.6 × 10^7 × 250 × 10^ -3 / 6×10^9
= 1.6 × 2.5 × 10^7 × 10^-1 × 10^-9 /6
Delta v = 0.66 × 10 ^ -3 m^3
so , value of decreased volume comes 0.66 × 10^-3 m^3 .
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QUESTION
A hydrulic press contain 250 litres of oil if it is subjected to an increased pressure of 1.6 × 10^7 pa . Find the decease in volume if boil = 6× 10^ 9 Nm^-2
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