Question

a hypermetropic person with near point 1m wants to read newspaper keeping it at a distance of 25cm the power of the corrective lens should be?​

Answer 1

Answer:

the corrective lens is convex lens

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Answer 2

The power of the corrective lens is + 3 D.

Explanation:

To calculate the power of the corrective lens, use lens maker formula.

$\frac{1}{f} =\frac{1}{u} -\frac{1}{v}$

Here f is the focal length of the lens, u is object distance and v is image distance.

For normal eye,  $u = - 25 cm$

and the lens used forms its virtual image at near point of hypermetropic eye,

$v = -1 m = - 100 cm$

Substitute the given values, we get

$\frac{1}{f} =\frac{1}{-100} -\frac{1}{-25}$

f = 33.33 cm = 0.33 m

So , power

$P=\frac{1}{f(m)}$

$P=\frac{1}{0.33m} =3D$

Thus,the power of the corrective lens is +3 D.

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