A hypothetical electrochemical cell is shown below
Θ Θ
A | A⁺ (xM) || B⁺ (yM) | B
The emf measured is +0.20 V. The cell reaction is
(a) A⁺ + e⁻ ⟶ A; B⁺ + e⁻ ⟶ B
(b) The cell reaction cannot be predicted
(c) A + B⁺ ⟶ A⁺ + B
(d) A⁺ + B ⟶ A + B⁺
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(c) A + B⁺ ---> A⁺ + B
Explanation:
Since the emf of the hypothetical electrochemical cell is positive (+0.20V), the choice of electrodes as mentioned in the convention is correct.
Anode reaction (oxidation):
A ---> A+ + e-
Cathode reaction (reduction):
B+ + e- ---> B
Cell reaction:
A + B⁺ ---> A⁺ + B, E(0-cell) = +0.20V
Hence Option C is the answer.
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