Question

A hypothetical element Z if found to have an atomic mass of 37.45 amu. Element Z has only two
isotopes, Z-37 and Z-38. The Z-37 isotope has a fractional abundance of 0.77 and isotopic mass of
37.24. What is the isotopic mass of the other isotope.
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Answer 1

Explanation:

This is the correct answer:

first we will take the total abundance=1%

then for Z37=.77%abundance and

for Z38=1-.77=.23%abundance

now, At. mass =37.24*.77+x*.23/1

=37.45=28.67+.23x

=37.45-28.67=.23x

=8.78=.23x

=x=8.78/.23

=x=38.15 ans