Question

a hypothetical germ cell contains 2n= 8 chromosome, determine the number of the following per daughter cell:
1. bivalent at zygonema
2. tetrads at pachynema
3. dyads at prophase 2
4. monads at anaphase 2

Answer 1

Answer:

dyads at prophase 2

Explanation:

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Answer 2

The number of bivalents, tetrads, dyads, and monads in the given deployed chromosome is 4, 4, 16, and 32 respectively.

The given "2n=8" chromosomes refer to 8 structures of the deployed chromosome.

1. bivalent at zygonema

Bivalent depends on the number of chromosomes. A pair of deployed chromosomes form a single bivalent. Thus, for 8 chromosomes, 4 pairs will be formed i.e. 4 bivalents.

Hence, the number of bivalents per daughter cell is 4.

2. tetrads at pachynema

Tetrads are structures with 4 chromatids i.e. 2 chromosomes which is the same as bivalent described above.

The number of tetrads is thus the same as the number of bivalents i.e. 4 here.

Hence, the number of tetrads per daughter cell is 4.

3. dyads at prophase 2

Each chromosome is said to have 2 dyads generally.

So, as the number of deployed chromosomes here is 8, the number of dyads will be twice that value i.e. 2 * 8 = 16.

Hence, the number of dyads per daughter cell is 16.

4. monads at prophase 2

Each chromosome is said to have 4 monads generally.

So, as the number of deployed chromosomes here is 8, the number of monads will be 4 times that value i.e. 4 * 8 = 32.

Hence, the number of monads per daughter cell is 32.

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